College Board Big Idea 1

Identifying and Correcting Errors (Unit 1.4)

Become familiar with types of errors and strategies to fixing them

  • Lightly Review Videos and take notes on topics with Blog
  • Complete assigned MCQ questions

Here are some code segments you can practice fixing:

alphabet = "abcdefghijklmnopqrstuvwxyz"

alphabetList = []

for i in alphabet:
    alphabetList.append(i)

print(alphabetList)

The intended outcome is to determine where the letter is in the alphabet using a while loop

  • What is a good test case to check the current outcome? Why?
  • Make changes to get the intended outcome.
letter = input("What letter would you like to check?")

i = 0

while i < 26:
    if alphabetList[i] == letter:
        print("The letter " + letter + " is the " + str(i) + " letter in the alphabet")
    i += 1

The intended outcome is to determine where the letter is in the alphabet using a for loop

  • What is a good test case to check the current outcome? Why?
  • Make changes to get the intended outcome.
letter = input("What letter would you like to check?")

for i in alphabetList:
    count = 0
    if i == letter:
        print("The letter " + letter + " is the " + str(count) + " letter in the alphabet")
    count += 1

This code outputs the even numbers from 0 - 10 using a while loop.

  • Analyze this code to determine what can be changed to get the outcome to be odd numbers. (Code block below)
evens = []
i = 0

while i <= 10:
    evens.append(i)
    i += 2

print(evens)    

This code should output the odd numbers from 0 - 10 using a while loop.

odds = []
i = 0

while i <= 10:
    odds.append(i)
    i += 2

print(odds)

This code outputs the even numbers from 0 - 10 using a for loop.

  • Analyze this code to determine what can be changed to get the outcome to be odd numbers. (Code block below)
numbers = [0,1,2,3,4,5,6,7,8,9,10]
evens = []

for i in numbers:
    if (numbers[i] % 2 == 0):
        evens.append(numbers[i])

print(evens)

This code should output the odd numbers from 0 - 10 using a for loop.

numbers = [0,1,2,3,4,5,6,7,8,9,10]
odds = []

for i in numbers:
    if (numbers[i] % 2 == 0):
        odds.append(numbers[i])

print(odds)

The intended outcome is printing a number between 1 and 100 once, if it is a multiple of 2 or 5

  • What values are outputted incorrectly. Why?
  • Make changes to get the intended outcome.
numbers = []
newNumbers = []
i = 0

while i < 100:
    numbers.append(i)
    i += 1

for i in numbers:
    if numbers[i] % 5 == 0:
        newNumbers.append(numbers[i])
    if numbers[i] % 2 == 0:
        newNumbers.append(numbers[i])

print(newNumbers) 

Challenge

This code segment is at a very early stage of implementation.

  • What are some ways to (user) error proof this code?
  • The code should be able to calculate the cost of the meal of the user

Hint:

  • write a “single” test describing an expectation of the program of the program
  • test - input burger, expect output of burger price
  • run the test, which should fail because the program lacks that feature
  • write “just enough” code, the simplest possible, to make the test pass

Then repeat this process until you get program working like you want it to work.

Important: Pay attention! It’s important.

menu =  {"burger": 3.99,
         "fries": 1.99,
         "drink": 0.99,
         }
total = 0

#shows the user the menu and prompts them to select an item
print("Menu")
for k,v in menu.items():
    print(k + "  $" + str(v)) #why does v have "str" in front of it?

#ideally the code should prompt the user multiple times
item = input("Please select an item from the menu")
print("total")
total= menu[item]

#code should add the price of the menu items selected by the user 
print(total)
Menu
burger  $3.99
fries  $1.99
drink  $0.99
total
3.99

Important: Pay attention! It’s important.

menu =  {"burger": 3.99,
         "fries": 1.99,
         "drink": 0.99,
         }
total = 0

#shows the user the menu and prompts them to select an item
print("Menu")
for k,v in menu.items():
    print(k + "  $" + str(v)) #why does v have "str" in front of it?

#ideally the code should prompt the user multiple times
item = input("Please select an item from the menu")
print("total")
total= menu[item]

#code should add the price of the menu items selected by the user 
print(total)
Menu
burger  $3.99
fries  $1.99
drink  $0.99
total
1.99

Important: Pay attention! It’s important.

menu =  {"burger": 3.99,
         "fries": 1.99,
         "drink": 0.99,
         }
total = 0

#shows the user the menu and prompts them to select an item
print("Menu")
for k,v in menu.items():
    print(k + "  $" + str(v)) #why does v have "str" in front of it?

#ideally the code should prompt the user multiple times
item = input("Please select an item from the menu")
print("total")
total= menu[item]

#code should add the price of the menu items selected by the user 
print(total)
Menu
burger  $3.99
fries  $1.99
drink  $0.99
total
0.99

Errors

  • I had troble writing code with while loop, where I looked at past assignments and tried to input while loop and switch the data about burger, fries and drink.
  • But I tried many times and there was always an error so I had to write some basic code to just display the price of what choice of item the user chose.